Given the acceleration, initial velocity, and initial position of a body moving along a coordinate line at time t, find the body's position at time t. a = 18, v(0) = -5, s(0) = 14

s = 18t^2 - 5t + 14
s = 9t^2 - 5t
s = 9t^2 - 5t + 14
s = -9t^2 + 5t + 14

add all the numbers and check the ones place.

the answer is 486. as the ones place is more than 4, the estimation will be the next 10 ie, 490

is there any photos or whatever?

well the answer to that is xoxoxo

step-by-step explanation:

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.