Given z1= sqrt 2 (cos(3pi/4)+ i sin (3pi/4)) and z2= (cos(pi/2)+ i sin (pi/2)), what is the value of z1-z2? A- cos(0)+isin(0)
B-cos(0)-isin(0)
C- cos(pi)+isin(pi)
D- cos(pi)-isin(pi)

Consider this equation. |y + 6| = 2 what can be concluded of the equation? check all that apply. there will be one solution. there will be two solutions. the solution to –(y + 6) = 2 will be also be a solution to the given absolute value equation. the solution(s) will be the number(s) on the number line 2 units away from –6. the value of y must be positive since the variable is inside absolute value signs.