Joseph is going on a trip and he needs to rent a car. He looks online and finds two companies that offer different pricing options for car rentals. Company A charges $0.25 per mile plus a $50 rental fee. Company B charges $0.45 per mile plus a $20 rental fee. What is the maximum number of miles that Joseph can drive in order for Company B to be a better buy? The company charges only for whole number mileage (not fractional increments of miles driven).

A) 125 miles
B) 149 miles
C) 150 miles
D) 151 miles

E.The price for travelling 150 miles is same for both company.

Step-by-step explanation:

We are given that Joseph is going on a trip and he needs to rent a car.

Company A

Charge $0.25  per mile plus  $50 rental fee.

Company B  charges 40.45 per mile plus $20 rental fee.

A.Total distance=150 miles

Company A

Charges for 150 miles=$37.5

Total charges=37.5+50=$87.5

Company B

Charges for 150 miles==$67.5

Total charge=20+67.5=$87.5

The price for travelling 150 miles is same for both company.

But if distance greater than 150 miles such 155  miles

Company A

Total charge=$88.75

Company B

Total charges=$89.75

Company A is better deal if Joseph more than 150 miles.

If distance 145 miles

Price form company A=$86.25

Price form company B=$85.25

Company B is better deal if Joseph travel less than 150 miles.

Hence, option E is true.

I hope this helps you <3333

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐