From the information given determine the quadrant in which the terminal point (determined by an angle with a measure of a) lies. Input I, II, III, or IV. If sin(θ)<0 and cos(θ)<0), then (x, y) lies in quadrant ___

If sin(θ)>0 and cos(θ)<0), then (x, y) lies in quadrant _

If sin(θ)>0 and cos(θ)>0), then (x, y) lies in quadrant _

If sin(θ)<0 and cos(θ)>0), then (x, y) lies in quadrant _
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If sin(θ)<0 and cos(θ)<0), then (x,y) lies in quadrant III.

If sin(θ)>0 and cos(θ)<0), then (x,y) lies in quadrant II.

If sin(θ)>0 and cos(θ)>0), then (x,y) lies in quadrant I.

If sin(θ)<0 and cos(θ)>0), then (x,y) lies in quadrant IV.

Step-by-step explanation:

Sine and cosine values, relation with quadrant:

Quadrant 1: Sine > 0, cosine > 0.

Quadrant 2: Sine > 0, cosine < 0.

Quadrant 3: Sine < 0, cosine < 0.

Quadrant 4: Sine < 0, cosine > 0.

If sin(θ)<0 and cos(θ)<0), then (x,y) lies in quadrant

Both negative, so III.

If sin(θ)>0 and cos(θ)<0), then (x,y) lies in quadrant

Sine positive, cosine negative, so II.

If sin(θ)>0 and cos(θ)>0), then (x,y) lies in quadrant

Both positive, so I.

If sin(θ)<0 and cos(θ)>0), then (x,y) lies in quadrant

Sine negative, cosine positive, so IV.

the answer is d on edge

step-by-step explanation:

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4