write an equarion of point slope form of the line that lasses through the point (2, -8) and has a slope of 4​

y = 4x -16

Step-by-step explanation:

y+8= 4(x-2)

y+8=4x-8

y= 4x - 16

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

angle addition postulate

2x=56

step-by-step explanation: