Help fast PLEASE this is my math exam review and I'm already failing
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x/3-10=8

x/3=18

x=48

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

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y

=

−

2

find the upper bound of the range.

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y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

54, jfvhgnjhvnjhcbnncjigjm

1.) 21

2.) 0.453

3.) 1.5

4.) 48

5.) $ 22

step-by-step explanation: