What is the equation of the line that passes through the point (-4, 2) and has a slope of -5/4?​

y = -5/4 x - 3   is the slope-intercept form

5x + 4y = -12    is the standard form

Step-by-step explanation:

Use the point-slope form:  

= (-4, 2)

y - 2 = -5/4(x + 4)       Multiply by 4 to remove the fraction

4y - 8 = -5(x + 4)

4y - 8 = -5x - 20

4y = -5x - 12

y = -5/4 x - 3   is the slope-intercept form

5x + 4y = -12    is the standard form

2 and 1.

step-by-step explanation:

plug in each answer. 0 doesn't work, 1 does. so does 2. 4 doesn't:

0 = 1 is not true.

2 = 2 is true.

4 = 4 is true.

8 = 16 is not true.

hope this !

triangle abc is reflected on the line x=-6.5 then reflected again on the x axis

step-by-step explanation: