A child’s shoe box measures 4" by 6" by 3". What is the longest pencil you could fit into this box?

5in

Step-by-step explanation:

Given data

Lenght= 4 in

Width= 6 in

Height= 3 in

Applying the Pythagoras theorem,

Let the longest pencil that could fit in be z

z^2= l^2+ h^2

z^2= 4^2+ 3^2

z^2= 16+9

z^2= 25

z= √25

z= 5 in

Hence the longest pencil is 5in

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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