Shin used a doubling and halving strategy to solve 25 times 68. Fill in the blanks in the arrays and the equations to represent her work

Step-by-step explanation:

Given

Required

Fill the array using doubling and halving

Question is incomplete, as the array is not given.

However, the solution is as follows:

Double 25 and half 68

Double 50 and half 34

The above is now easy to solve

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2