I’ll give Which figure is described below?
The locus of points in a plane
equidistant between y = 5 and
y = -3.
A. 1 line
B. 1 plane
C. 2 planes
D. 2 lines
Ok

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

your answer is b ^w^ hope i

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step-by-step explanation: