If the volume of a cube is 64units3, what is the area of one of the face of the cube?

16 units²

Step-by-step explanation:

Volume:

v = s³

64 = s³

Take the cube root of both sides

4 = s

Area:

a = s²

a = 4²

a = 16 units²

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )