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A class contains $$5 girls and $$7 boys. Two are selected for a class committee. What is the probability that a girl and boy are selected? Probability=
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Which of these equations, when solved, gives a different value of x than the other three? a9.1 = -0.2x + 10 b10 = 9.1 + 0.2x c10 β 0.2x = 9.1 d9.1 β 10 = 0.2x
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The statement tan theta= -12/5, csc theta=-13/12, and the terminal point determained by theta is in quadrant two
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Given a normal distribution with Β΅ =50 and Ο =4, what is the probability that 5% of the values are less than what x values? between what two x values (symmetrically distributed around the mean) are 95 % of the values? instructions: show all your work as to how you have reached your answer. donβt simply state the results. show graphs where necessary.
Answers: 3
A class contains $$5 girls and $$7 boys. Two are selected for a class committee. What is the probabi...
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