A die is rolled twice. What is the probability of showing a 3 on the first roll and an even number on the second roll?

Assumption:-Dice referred here is fair six-sided dice with numbers(1,2,3,4,5,6) .

Therefore the probability of showing 3 on the first roll=probability of occurrence of 3 in(1,2,3,4,5,6) which is 1/6 since 3 appears once in 6 numbers.

Probability of odd number on the second roll = probability of occurrence of odd numbers(1,3,5) in (1,2,3,4,5,6) which is equal to 3/6 equivalent to 1/2.

Probability of complete event =probability of showing a 3 on the first roll and an odd number on the second roll.

Since the occurrence of 3 on first roll is independent of the occurrence of an odd number on the second roll, Probability of complete event =(probability of showing a 3 on the first roll) x (probability of an odd number on the second roll)=1/6x1/2=1/12.

15%

step-by-step explanation:

use the table and count the number of guesses that has two correct answers.

the following are two correct answers

10010, 01100, 11000

a total of 3 numbers having 2 correct guesses out of 20 questions.

probability of getting 2 correct guesses = the number of questions getting 2 correct answers / total number of questions.

= 3/20

to convert it into percent multiply by 100, we get

= 3/20 * 100

= 15%

the answer is 15%

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step-by-step explanation: