Let us call a function f : A → R anti-continuous if it satisfies the following condition. For every point x ∈ R there exists > 0 and δ > 0 such that for all y ∈ A
0 < |x − y| < δ =⇒ |f(x) − f(y)| > .
(a) Show that there exists an anti-continuous function f : Q → R.
(b) Show that there is no anti-continuous function f : R → R.

Aye I've you caught now ya wee bastаrd

Step-by-step explanation:

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b