A circle is centered about the point (2, 0). The point (0, 1) is on the circle. Which statement proves that the point (4, 1) is also on the circle?

Step-by-step explanation:

the circle is at the origin and (0,4) is a point on the circle then the radius of the circle is:

r^2=0^2+4^2

r^2=16

r=4

so we can check that the other point is four units from the origin and thus also on the circle...

d^2=2^2+6^2

d^2=4+36

d^2=40

since d^2>r^2, (2,6) is outside the circle

c. (3,2,6) is the answer.