The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = y minus 1 equals StartFraction one-fourth EndFraction left-parenthesis x minus 12 right-parenthesis.(x – 12). What is the standard form of the equation for this line?

Given:

The line passes through the two points (–4, –3) and (12, 1).

The point-slope form of the equation of the line is:

To find:

The standard form of the equation for this line.

Solution:

The standard form of a line:

The given point-slope form of the equation of the line is:

Multiply both sides by 4.

Interchanging the sides, we get

Therefore, the standard form of the equation for this line is .

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph