Determine which relation is a function. {(0, 0), (1,−1), (2,−4), (3,−9), (4,−16)} {(2,−6), (2,−2), (2, 0), (2, 3), (2, 7)} {(2, 2), (1, 1), (0, 0), (1, −1), (2,−2)} {(3, 2), (4, 3), (5, −4), (5, 4), (6, 5)}

1

Step-by-step explanation:

{(0, 0), (1,−1), (2,−4), (3,−9), (4,−16)}

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

a_n = a_1 + (n - 1)d

the first term is 6.

the common difference d = ?

when you find d, replace n with 7 and d with the common difference to find your answer.