A school administrator claims that 85% of the students at his large school plan to attend college after graduation. The statistics teacher at this school selects a random sample of 50 students from this school and finds that 76% of them plan to attend college after graduation. The administrator would like to know if the data provide convincing evidence that the true proportion of all students from this school who plan to attend college after graduation is less than 85%. What are the values of the test statistic and P-value for this test? Find the z-table here.

z = –1.78, P-value = 0. 0375
z = –1.78, P-value = 0. 0750
z = 1.78, P-value = 0.0375
z = 1.78, P-value = 0. 0750

The first where z = -1.78 and p-value = 0.0375 would be the correct answer

Hope it helps

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all