What is the height of the cone below? ​

The height of the cone is h = 27

Formula:-

Step 1:-

The volume of the cone is  V=\frac{1}{3} (base)(height)V=31(base)(height)

Given volume is V= 45 in^ 3

Given base of the cone is B= 5 in^2

Step 2:-

by using formula, we get solution

45 = \frac{1}{3} (5)(h)45=31(5)(h)

cross multiplication, we get

\frac{45 x 3}{5} =h545x3=h

now simplification, the height of the cone is h = 27

sauce:

27 in.

Step-by-step explanation:

Firstly, let's look at what we do know. We need to find the height of a cone and we know the area of the base (B) and we know the volume of the cone.

The first step is to determine the radius of the base, which we can use later.

The area of a circle is A = π r^2, so when we plug in the given information

5 = π r^2

And now we can solve for the radius

5/π = r^2

√(5/π) = r

r = 1.26

Now that we have the radius of the base, we can find the height of the cone using the volume formula.

V = π r^2 (h/3)

45 = π (1.26)^2 (h/3)

45 = π (1.59) (h/3)

45/(1.59π) = h/3

9.01 = h/3

3(9.01) = h

h = 27 in

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

36

step-by-step explanation: