​Andy is A years old. His brother Ron is R years old. Andy multiplies his own age by 3. He then subtracts twice Ron's age. ​The answer is 6. ​Ron subtracts his age from Andy's age. ​The answer is −2 a​Write a pair of simultanous equations that model Andy's and Ron's ages.

the  pair of simultanous equations that model Andy's and Ron's ages are

3A-2R=6Equation 1

R-A =2Equation 2

Andy is 10 Years and Ron is  12 years  

Step-by-step explanation:

Andy's age is represented as A

and Ron';s age is represented as R

Now if Andy multiplies his own age by 3. He then subtracts twice Ron's age. ​The answer is 6 can be expressed mathematically as

3A-2R=6

And if Ron subtracts his age from Andy's age. ​The answer is −2  can be expressed as

R-A =2

Therefore the  pair of simultaneous equations that model Andy's and Ron's ages are

3A-2R=6Equation 1

R-A =2Equation 2

Solving becomes

3A-2R=6Equation 1

R-A =2Equation 2

Make R subject formulae in equation 2

R =2+A

Putting R =2+A in equation 1

3A-2(2+A)=6

3A -4-2A =6

A-4=6

A=6+4=10

From eqn 2,

R-A =2

R-10 =2

R=10+2=12

Andy is 10 Years and Ron is  12 years  

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3