A model rocket is launched off the top of a platform. The height of the rocket is given by the function h(t) = -4.9t2+ 86t + 2.1, where h(t) is the height in meters and t is the time in seconds. When will the rocket's height be 200m?

t = 14.82 and 2.72secs

Step-by-step explanation:

Given the function of the rocket height expressed as;

h(t) = -4.9t^2+ 86t + 2.1

if the rocket height is at 200m, then;

200 = -4.9t^2+ 86t + 2.1

multiplying through by 10

2000 = -49t^2 + 860t + 21

49t^2 - 860t - 21 + 2000 = 0

49t^2 - 860t + 1979 = 0

Factorize

t = 860±√(860)²-4(49)(1979)/2(49)

t = 860±√739,600-387,884/98

t = 860±√351,716/98

t = 860±593.06/98

t = 860+593.05/98 and 860-593.05/98

t = 1,453.05/98 and 266.94/98

t = 14.82 and 2.72secs

These are the times

step-by-step explanation:

describing distributions is one of the key skills you’ll need to earn a high score on the ap statistics exam. if you need proof of this, just flip through some past exam questions, which can be found at the collegeboard website. you’ll notice that the first free response question is almost always a question requiring you to look at a graph and describe it.

step-by-step explanation: just trying to get points sorry : (