The length of a rectangle is 7cm more than twice the width. When just the width is tripled, the perimeter of the resulting rectangle is 74cm. What are the original dimensions of the rectangle?

Length = 27cm

Width = 10cm

Step-by-step explanation:

Let the length of the rectangle be x

Let the width be y

If the length of a rectangle is 7cm more than twice the width, then;

x = 2y + 7

Since P = 2(x+y)

P = 2(2y+7+y)

P = 2(3y+7)

P = 6y+14

If the width is tripled, P = 74

74 = 6y+14

6y = 74-14

6y = 60

y = 10

Since x = 2y+ 7

x = 2(10) + 7

x= 20+7

x = 27

Hence the original dimension is 27cm by 10cm

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

step-by-step explanation:

first you will have to convert 3/4 into a decimal

which is .75

then you will have to divide 1.5 by .75

which is 2

no you have to divide