Complete the following table using the equation: y = x squared x -3 -1 0 1 3 y Plot the points on a graph and determine which graph best represents the equation. Graph A On a coordinate plane, a parabola opens up and goes through (negative 2, 4), has a vertex at (0, 0), and goes through (2, 4). Graph B On a coordinate plane, a parabola opens down and goes through (negative 2, negative 4), has a vertex at (0, 0), and goes through (2, negative 4). a. -9, -1, 0, -1, -9; Graph B b. 9, 1, 0, 1, 9; Graph B c. 9, 1, 0, 1, 9; Graph A d. -9, -1, 0, -1, -9; Graph A Please select the best answer from the choices provided A B C D

c. 9, 1, 0, 1, 9; Graph A

Step-by-step explanation:

The given equation is presented as follows;

y = x²

The values of 'x' are -3, -1, 0, 1, 3

The range of the values of 'y' are; (-3)² = 9, (-1)² = 1, 0² = 0, 1² = 1, 3² = 9

9, 1, 0, 1, 9

The completed table is presented as follows;

The values can be extended using the equation to include points, x = -2, y = (-2)² = 4, and x = 2, y = 2² = 4

To give a graph that passes through the point (-2, 4) and (2, 4)

Given that the coefficient of x² is positive, the graph opens up

Therefore, the graph that best represent the equation is c, 9, 1, 0, 1, 9; Graph A On the coordinate plane, a parabola opens up and goes through (-2, 4), has a  vertex at (0, 0), and goes through (2, 4).

he spend 5.1 minutes chatting with his friends

step-by-step explanation:

2/5+1/2=9/10

6/1-9/10=5 1/10

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.