Circle A is located at (6,5) and has a radius of 4 units. What is the equation of a line that is tangent to circle A from point C (2,8)? x=2
y = -0.75x + 9.5
y = 1.33x + 1.66
x = 8

answer:

what is your question that you ask

step-by-step explanation:

a

step-by-step explanation:

the answer is a

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

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