A bag contains 8 red marbles, 6 blue marbles and 7 green marbles. If two marbles are drawn out of the bag, what is the probability, to the nearest 1000th, that both
marbles drawn will be red?

.029

Step-by-step explanation:

The probability of the first being blue is 6/17, the second is 5/16 and the third is 4/15.  Multiply these together to get the total probability:

6/17 x 5/16 x 4/15 = .029

ps: have a nice day :)

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

the answer is a

step-by-step explanation: