V+2/v + 4/3v =11
How to solve this ?

0.189

4.525

Step-by-step explanation:

v/1 + 2/v + 4v/3 = 11

we can eliminate denominators if we distribute 3v to each term:

3v(v/1 + 2/v + 4v/3) = 3v(11)

3v² + 6 + 4v² = 33v

7v² - 33v + 6 = 0

factor this trinomial:

there are no factors of 6 that would add to -33 so we can use the quadratic formula to solve:  (-b ± √b²-4ac) / 2a

a = 7

b = -33

c = 6

[33 ± √(-33)² - 4(7)(6)] / 2(7)

(33 ± √1089 - 168) / 14

(33 ± √921) / 14

(33 ± 30.35) / 14

(33+30.35) / 14 =  4.525

(33-30.35) / 14 =  0.189

55/i dont know i do it for the points

step-by-step explanation:

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.