Which THREE sets of ordered pairs represent functions? A) {(15, –3), (–6, 9), (–3, 0), (–1, 16), (5, 5)} B) {(6, 0), (–12, –16), (–6, 10), (20, –7), (16, 9)} C) {(12, –18), (15, 1), (12, 5), (0, 9), (–5, –17)} D) {(–13, 4), (7, –15), (–13, 9), (6, –12), (–18, 0)} E) {(10, 9), (–2, –16), (–6, 7), (5, 8), (8, –16), (–11, 9)}

A, B, and E

Step-by-step explanation:

A function has only ONE out put for each input. For example in C 12 has two outputs, -18 and 5 so that set is NOT a function.

30005

yes ok                                            

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true