The area of a rectangle is represented by the expression 2x2 + 10x + 12. Daniel is convinced that the dimensions of this rectangle could be (2x + 4) and (x + 3) or (x + 2) and (2x + 6). Do you agree or disagree with Daniel? Use words to justify your opinion.

I agree with daniel

Step-by-step explanation:

Given the area of a rectangle expressed as;

A(x) = 2x²+10x+12

On factorizing;

A(x) = 2x²+6x+4x+12

A(x) = 2x(x+3)+4(x+3)

A(x) = (x+3)(2x+4)

since A(x) = l(x)w(x)

Hence the legnth and width of the rectangle are 2x+4 and x+3.

Also A(x) = 2x²+6x+4x+12 can be factorized as;

A(x) = 2x²+4x+6x+12

A(x) = 2x(x+2) + 6(x+2)

A(x) = 2x+6(x+2)

Therefore I agree with Daniel. The factor differs due to the difference in arrangement of 4x and 6x in the expression. Precedence of values affects the final factors

yes   because as the functions are graphed they eventually will intersect unless otherwise

step-by-step explanation:

150.6

all i did was i multiplied 5.02 by 30