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The point-slope form in the graph below of the line is 0-2=-2(6-5) because of the point I chose that rests on the x axis (6,0) and the specific formula being used, which is y-y₁=m(x-x₁). It can also be y=2x-12 if you're looking for slope-intercept, because the line crosses 12 and is going down, hence the negative.

Step-by-step explanation:

0 can be found by finding the second point. In this case, the second point would be 0 because I chose (6,0) as my second coordinate. 2 can be found because of the first point, whose coordinates are (5,2). Now that the coordinates are known, I can find the rest of the point-slope equation.

Here's what we got so far: 0-y₁=m(6-x₁)

This is the part where the coordinates of the point given are used. The coordinates of the point given are (5,2). Plug 5 in for x₁ because x₁ is for the x of the given point, and plug 2 in for y₁, because y₁ is the y of the given point, and the coordinates I selected for the second ungiven point are (6,0).

Here's what we have now: 0-2=m(6-5)

Finding the "m" will be easy, because the "m" is the slope, and the slope is negative because the line is going down. To find the slope you will have to go 2 down from the point and 1 to the right. Then, you'll find out the slope is -2 and why I chose my second point to be (6,0)

The equation, after finding all the data, is 0-2=-2(6-5)

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step-by-step explanation: