Francine bought a TV that is 31 inches tall and 57 inches wide. She is going to mount it on the wall in her living room. The wall is 8 feet wide and 9 feet tall. How many square inches of the wall will not be covered by the TV once it is mounted?

the tv would actually be too big for the wall, or cover all of that wall and then some.

Step-by-step explanation:

so the formula for this is going to be lxw

notice the units are different. this is an easy fix. either divide the inches by 12 or multiply the ft by 12. (12 inches in a foot)

tv=  31in x 57in= 1,767 in2

wall=  8ftx9ft= 72 ft2

if the wall is 72ft2, then it would be 864in2

(72in2 x 12= 864in2)

if the tv is 1,767 in2 and the wall is  864in2 ; the tv would actually be too big for the wall; or cover all of that wall and then some.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

the aswere is the one with all 8's and the second one is with the 10,8 and 6

step-by-step explanation: