If a fair coin is tossed 8 times, what is the probability, to the nearest thousandth, of getting exactly 2 tails?

0.109

Step-by-step explanation:

Probability is expressed by the number of desirable outcomes over the total outcomes. The total outcomes would be 2^8 because there are two possibilities in each flip, and using the fundamental counting principle, you get 2^8 total outcomes. Next, to find the amount of situations where you only flip two tails, you use 8 choose 2 because we are looking for the amount of ways you can choose 2 out of the 8 to be tails. 8 choose 2 is the same as:

8! / (6! x 2!) - 28

So, the probability is:

28 / 2^8 or 28/256

As a decimal, this is: 0.109375

And rounded to the nearest thousandth it's 0.109

step-by-step explanation:

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all