There are five favorite parking spaces in the game, Shopping Extravaganza. You receive
two tokens if you land on Parking Space #1,
six tokens if you land on Parking Space #2,
two tokens if you land on Parking Space #3,
three tokens if you land on Parking Space #4,
and seven tokens if you land on Parking
Space #5. You have an equal chance of
landing on each space. What is the expected
value of the number a tokens during a play in
the game?

Free Parking is a corner square on the board diagonally opposite to Go. When a player lands here nothing happens and they move off the space on their next turn.

The only exception is in the Monopoly City version, where landing on the space grants the player the 'Rent Dodge' card, regardless of if another player has it or not. And Cheater's Edition, where landing on the space grants the player a Community Chest card or Chance card.

Step-by-step explanation:oo like this you have to do

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

answer: ♡♡♡♡♡♡♡♡♡♡

step-by-step explanation: