SOMEONE PLS HELP ME

I ATTACHED A PIC​

See solution below

Step-by-step explanation:

The centre of the circle will be the midpoint of both coordinate

Given the coordinates P(-7, -10) and Q = (3,2)

X = x1+x2/2

X = -7+3/2

X = -4/2

X = -2

Y = y1+y2/2

Y = -10+2/2

Y = -8/2

Y = -4

Hence the centre is at (-2, -4)

The distance between the coordinates will be the diamter

PQ =√(3+7)² + (2+10)²

PQ =√(10)² + (12)²

PQ = √100+144

PQ =√244

radius = √244/2

Get the equation

(x-a)² + (y-b)² = r²

(x -(-2))² + (y-(-4))² = (√244/2)²

(x +2)² + (y+4)² = (244/4)

(x +2)² + (y+4)² = 61

This gives the required equation

the least common denominatore of 7 and 2 is 9

step-by-step explanation:

7+2=9