Use the quadratic formula (x - 6)2 + 3 to answer questions 15 - 20. 15. a =
a. 1
b. 4
1
c.
4
d. 6
16. k=
1
a.
4.
b. 6
c. 2
d. 3
17. The vertex of the parabola would be located at which coordinates?
a. (-6,3)
b. (6,3)
c. (3,-6)
d. (3,6)
18. The parabola would open
a. Upwards
b. Downwards
c. To the left
d. To the right
19. The axis of symmetry is located at x =
1
a.
4
b. 6
c. 2
d. 3
20. Because of the value of the leading coefficient, the parabola would have a
opening.
a. Narrow
b. Wide
c. Left
d. Right

Evaluate 8x2 + 9x − 1 2x3 + 3x2 − 2x dx. solution since the degree of the numerator is less than the degree of the denominator, we don't need to divide. we factor the denominator as 2x3 + 3x2 − 2x = x(2x2 + 3x − 2) = x(2x − 1)(x + 2). since the denominator has three distinct linear factors, the partial fraction decomposition of the integrand has the form† 8x2 + 9x − 1 x(2x − 1)(x + 2) = correct: your answer is correct. to determine the values of a, b, and c, we multiply both sides of this equation by the product of the denominators, x(2x − 1)(x + 2), obtaining 8x2 + 9x − 1 = a correct: your answer is correct. (x + 2) + bx(x + 2) + cx(2x − 1).