In a set of three lines, a pair of parallel lines is intersected by a transversal. The intersection forms eight special angles. Two of the special angles, A and B, are corresponding angles.

For the set of parallel lines intersected by a transversal, A = 4x and B = 2(x+14).

1. Use an equation to represent the corresponding angle relationship between A and B.

2. Use the equation to find the measures of A and B.

PLEASE HELP!!! Will mark brainliest and give thanks:)

a.) 4x = 2(x + 14)

b.) Measure of A = 56°

    Measure of B = 56°

Step-by-step explanation:

We know that,

When two lines are crossed by another line transversal line , the angles in matching corners are called corresponding angles.

Also,

When two lines are parallel then the Corresponding Angles are equal.

Given that,

A = 4x and B = 2(x+14).

i.e.

∠A = 4x and ∠B = 2(x+14)

a.)

Now,

As A and B are parallel

So,

∠A = ∠B

⇒4x = 2(x + 14)                  

(This is the equation that represent the corresponding angle relationship between A and B.)

b.)

Now,

⇒4x = 2x + 2(14)

⇒4x = 2x + 28

⇒4x - 2x = 28

⇒2x = 28

⇒x = 14

So,

we get

∠A = 4(14)

      = 56

⇒∠A = 56°

and

∠B = 2(14 + 14)

     = 2(28)

     = 56°

⇒∠B = 56°

∴ we get

Measure of A = 56°

Measure of B = 56°

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.