Find​ (a) the orthogonal projection of b onto Col A and​ (b) a​ least-squares solution of Axequalsb. Aequals[Start 3 By 2 Matrix 1st Row 1st Column negative 1 2nd Column 4 2nd Row 1st Column 1 2nd Column 8 3rd Row 1st Column negative 1 2nd Column 4 EndMatrix ]​, bequals[Start 3 By 1 Matrix 1st Row 1st Column 12 2nd Row 1st Column negative 4 3rd Row 1st Column 2 EndMatrix ]a. The orthogonal projection of b onto Col A is ModifyingAbove Bold b with caretequals nothing. ​(Simplify your​ answers.)

step-by-step explanation:

b and c

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

im pretty sure its

(8,15)

step-by-step explanation:

6x = 48

i hope this . 6 cards each and a total of $48. dvide each side by 6 and you will have your answer.