Find the least common multiple of 11z^3+110z^2+99z and 14z^2+112z-126

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step-by-step explanation:

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629

the answer to this would be 5x^3-6x^2-24 over 3x^2

hope this if needed hmu