The point (-3, 1) is onlthe terminal side of angle O, in standard position. What are the values of sine, cosine, and tangent of O? Make sure to show all work.

cos(θ) =  -3/√10

sin(θ) =   1/√10

tan(θ) =  -1/3

Step-by-step explanation:

When we have a point (x, y), the angle generated between the positive x-axis and a ray that connects the origin and the point, is defined by:

cos(θ) = x/(√(x^2 + y^2))

sin(θ) = y/(√(x^2 + y^2))

tan(θ) = y/x

Now we have the point (-3, 1), then we have:

x = -3

y = 1

√(x^2 + y^2) = √((-3)^2 + 1^2) = √10

Then we just need to replace these values in the given formulas:

cos(θ) = x/(√(x^2 + y^2)) = -3/√10

sin(θ) = y/(√(x^2 + y^2)) =  1/√10

tan(θ) = y/x = 1/-3 = -1/3