<3 pwease help will do anything lol <3 2. A 480 Ω resistor is connected in series to a 360 Ω resistor and a 120-V power supply.
a. Draw the circuit.

b. Calculate the equivalent resistance of the circuit.

c. Calculate the current through the battery.

d. How much current is passing through each resistor?

e. Calculate the voltage drop across each resistor.

f. How does the voltage drop across each resistor compare to the voltage of the battery

I just answered a so let's start with b :

b. The equivalent resistance of series

resistances is equal to their sum

Thus :

equivalent resistance = 480 + 360

equivalent resistance = 840

c.

I = V ÷ R

I = 120 ÷ 840

I = 0.1428 A

d. 0.1428 A

e. 480 ===》 120 - ( 480 × 0.1428 ) =

120 - 68.544 =

51.456

360 ===》 120 - ( 360 × 0.1428 ) =

120 - 51.408 =

68.592

f. 480 ===》68.544 lower than battery

360 ===》 51.408 lower than battery

if y=4x then you will substitute 4x in for y in the second equation.

8x + 4x = 18 combine like terms

12x = 18 divide by 12 on both sides

x = 18/12 or 3/2

now replace x in the first equation with 3/2 to get

y = 4 3/2

y = 6

the answer is a

(3/2,6)

hope that .

brainliest is always apprectiated