H(-4), h(0), h(4), h(8) h(x)= {-(x+1)^2 + 7, x<2
{ -1/3x, x>4

h(-4)=
h(0)=
h(4)=
h(8)=

PLEASE HELP

9514 1404 393

  see attached

Step-by-step explanation:

The first two x-values, -4 and 0, fall in the first part of the function definition.

There is no function definition for x = 4, as the second part only applies for x > 4.

The last x-value, 8, falls in the second part of the function definition.

The function is evaluated by putting the x-value where x is in the expression and doing the arithmetic. For example, ...

  h(-4) = -(-4+1)^2 +7 = -(-3)^2 +7 = -9 +7 = -2

  h(0) = 6

  h(4) = undefined

  h(8) = -8/3

i can answer this question sweetie!

step-by-step explanation:

step-by-step explanation: