A pocket contains 2 pennies, 2 nickels, 1 quarter and 4 dimes. What is the probability of randomly choosing a dime two times in a row, if the first coin drawn is not replaced?

1/6

Step-by-step explanation:

Probability calculates the likelihood of an event occurring. The likelihood of the event occurring lies between 0 and 1. It is zero if the event does not occur and 1 if the event occurs.

For example, the probability that it would rain on Friday is between o and 1. If it rains, a value of one is attached to the event. If it doesn't a value of zero is attached to the event.

probability of choosing dimes twice = total number of dimes / total number of coins

At first pick = 4/9

because there is no replacement, dimes and total coins reduce by 1 and

second pick = 3/8

4/9 x 3/8 = 1/6

find the vertical and horizontal asymptotes of the function f x = 5 x − 1 . to find the vertical asymptote, equate the denominator to zero and solve for . since the degree of the polynomial in the numerator is less than that of the denominator, the horizontal asymptote is .

step-by-step explanation:

can i see a photo of the question so i can you?