Quadratic equation whose vertex is (2,3) and y intercept is 11

y = 2(x - 2)² + 3      vertex form

y = 2x² - 8x + 11     standard form

Step-by-step explanation:

Vertex form

y = a(x - h)² + k

(h, k) = (2, 3)

y = a(x - 2)² + 3

To find "a" plug in the y-intercept (0, 11)

11 = a(-2)² + 3

11 = 4a + 3

Subtract 3 from both sides

8 = 4a

a = 2

y = 2(x - 2)² + 3

Expand

y = 2(x² - 4x + 4) + 3

y = 2x² - 8x + 11

answer:

step-by-step explanation:

80 the answer is 80

step-by-step explanation: