it rained nine days in the month of april .based on this ,what is the probaility that is does not rain on the first day of may?​

Explanation:

There are 30 days in April. Since it rained 9 of those days, the empirical probability of it raining in April is 9/30 = (3*3)/(3*10) = 3/10.

If we assume that the same conditions (ie weather patterns) hold for May, then the empirical probability of it raining in May is also 3/10. By "raining in May", I mean specifically raining on a certain day of that month.

The empirical probability of it not raining on the first of May is therefore...

1 - (probability it rains)

1 - (3/10)

(10/10) - (3/10)

(10-3)/10

7/10

We can think of it like if we had a 10 day period, and 3 of those days it rains while the remaining 7 it does not rain.

answer: 0,6

step-by-step explanation:

this would make it the y intercept.

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