Help plz ! find the measure of the central angle of an arc with length 5pi units and radius of 4.5 units

Angle of Arc θ = 200°

Step-by-step explanation:

Given:

Length of arc = 5π

Radius of circle = 4.5 unit

Find:

Angle of Arc θ

Computation:

Using length of arc formula

Length of arc = [θ/360][2πr]

Putting value or length of arc and radius in given formula;

5π = [θ/360][(2)π(4.5)]

5π = [θ/360][9π]

5 = [θ/360][9]

5 =  [θ/40]

θ = 40 x 5

θ = 200

Angle of Arc θ = 200°

cut 138 centimeters off

step-by-step explanation:

250-112 = 138

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3