Factor problems 9 - 12 by using the difference of squares method. 12. x2 + 100

A. (x + 10)(x – 10)
B. (-x + 10)(x – 10)
C. (x + 10)(x + 10)
D. This polynomial cannot be factored by using the difference of squares method.
E. (x - 10)(x – 10)
F. (-x + 10)(-x – 10)

351°f

step-by-step explanation:

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40