Part A: Students from 4 towns attend a conference. Each town is assigned a number from 1 to 4. Drag yes or no next to the first sentence. Yes or No

A number is drawn and replaced 6 times. Is this a fair way to pick 6 members to give each town representation? _

Part B: What is the probability that Town 1 will have at least 1 representative after 6 number draws, to the nearest percent?

probability = _ %

Part A - No

Part B - 100 %

Step-by-step explanation:

Part A.

This is because, a fair chance requires that each member has the same probability of being picked.

Since there are 4 towns, a fair chance would be 1/4.That is, 1 out of every town.

Part B

The probability of at least 1 representative after 6 number draws is P(at least 1)  = 1 - P(none from Town 1)

P(none from town 1) = 0

P(at least 1)  = 1 - P(none from Town 1)

P(at least 1)  = 1 - 0 = 1

In percentage 1 × 100 % = 100 %

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

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