Mathematics, 26.05.2021 22:10 woebrooke11
Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis. y=x2−12x+12
1 point in common; vertex on x-axis
2 points in common; vertex above x-axis
no points in common; vertex above x-axis
2 points in common; vertex below x-axis
Answers: 3
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36x2 + 49y2 = 1,764 the foci are located at: (-√13, 0) and (√13,0) (0, -√13) and (0,√13) (-1, 0) and (1, 0)edit: the answer is (- the square root of 13, 0) and (the square root of 13, 0)
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Without drawing the graph of the equation, determine how many points the parabola has in common with...
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