A right circular conical tank of height 1 foot and radius 1 foot at the top is full of water. Taking the density of the water to be 60 pounds per cubic foot, how much work in foot-pounds is required to pump all the water up and over the top of the tank

Step-by-step explanation:

Height= 1 foot

Radius= 1 foot

Density= 60 pounds per cubic foot

Density = mass/ volume

Vol of cone= 1/3× 22/7 ×(radius^2)

=1/3×22/7×1×1

=22/21

Mass=volume × density

= 22/21 × 60

=440/7

Energy = mgh

= 440/7 ×10 × 1

= 628.57 foot pounds

right

step-by-step explanation:

add 5 subtract 1

step-by-step explanation: