Please solve this question

it would be y=0

Step-by-step explanation:

because y+6y+9y=0

you basically add 6y+y=7y because the y that's by its self counts as 1

then you 7y+9y=16y

then it would be 16y=0

hope this helps out believe it's right

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

i’m kinda new to precal but your answer should be 21. hope i got it right.

step-by-step explanation: