Can some one find the vertex for g(x)8x^2-14x+3 Using decimals if necessary

The vertex of an up - down facing parabola of the formy = ax" + bx + c is xy =

The parabola params are:

a = 8, b = -14, c =3

=-(-14)/2·8

simplify

=-(-14)/2·8

Plug in =7/8to find the value

= -25/8

Therefore the parabola vertex is

(7/8 , -25/8)

If a < 0, then the vertex is a maximum value

If a > 0, then the vertex is a minimum value

a = 8

Minimum(7/8 , -25/8)

understand that i don't know the answers

will someone answer his question

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11 -1> 1 -1+ a

-12 > a